the sum of the selling prices of 2

toys having the same cost price and

sold at profits of5% and 10% is

1032.then the cost price of each

toy is…

a bicycle was sold at a gain of 20%.

had it been sold for rs.89 more,the

gain would have been 25%.find the

cost price of the bicycle.

a vendor bought a 5 lemons for rs. 1. how many lemons can be bought for rs.7 to gain 50/3

a dealer buys goods. at 15% off the list price. he wants to make a profit of 20% after allowing. a discount of 10% . at what price above the list price. should he mark the goods?.

a trader marks a television. 20% above the cost price and allows a discount of 10% . if the profit earned is rs.544,then what is the cost price of the television?

a student. buys 3 pencils for rs.4 and sells all atv4 for rs.5. his gain or loss percent is..

a shopkeeper sold an article. at 5% profit . if he had sold it at a profit of 35/2.% the profit would. have. been. rs.25 more.what is the cost price of the article .

## Explain These Math Problem…?

December 23rd, 2012 admin

1) Let the cost price of each article be Rs X

1.05X + 1.1X = 1032

2.15X = 1032

X = 1032/2.15 = Rs 480 ANSWER

2) Let the cost of cycle be Rs 100x

20% profit = sold for Rs 120x

25% profit = Rs 120x + Rs 89

125x = 120x +89

5x = 89

100x = 89 X 20 = Rs 1780 ANSWER

3) Question is not clear

4) Let the list price be Rs 100x

15% off = Rs 85x = cost

20% profit = 1.2 X 85 = Rs 102x

Sale price after 10% discount is Rs 102x

So marked price = 100/90 X 102x = Rs 113.33x

Marked price – cost = Rs 13.33x over the list price ANSWER

5) Cost = Rs 100x

20% profit = Rs 120x

10% discount = Rs 12x

Sale price = Rs 108x

8x = Rs 544

100x = 100/8 X 544 = Rs 6800 ANSWER

6) Cost per pencil = Rs 4/3

Sale price per pencil =Rs 5/4

loss = 5/4 – 4/3 = 15/12 – 16 /12 = – 1/12

loss % = 8.33/ 133 X 100 = 6.26% loss

7) Cost = Rs 100x

5% profit = Rs 105x

35/2% profit = Rs 117.50x

117.50x = 105x + 25

12.50x =25

100x = Rs 200 ANSWER

-first problem

the equation is 2x + (15x/100) = 1032 (where X is the original price of one toy)

when you solve this equation, you obtain that the price of each toy is X=480

-second problem

the equations are: X+(20X/100)=Y and X+(25X/100)=Y+89 (where X is the price of the bicycle and Y is the is the selling price of the bicycle)

when you solve this equation, you obtain that the price of the bicycle is X=1780

-third problem

this problem is unclear (to gain 50/3 what)

-fifth problem

the equation is (10X/100)=544 where X is the cost of the television

when you solve this equation , X=5440

-sixth problem (what does atv4 stand for)

-seventh problem

the equations are (5X/100)+X=Y and (35X/200)+X=Y+25

when you solve this system of equations, you find that the price of the article is X=200

ASK ONLY ONE QUESTION AT A TIME.

1) Let the cost price of each toy = Rs x

Selling price of the 1st toy = Rs (x + 5% of x) = Rs (x + x/20) = Rs 21x / 20

Selling price of the 2nd toy = Rs (x + 10% of x) = Rs (x + x/10) = Rs 11x / 10

Sum of the Selling prices of the 2 toys = Rs (21x / 20 + 11x / 10) = Rs 43x / 20

As per the question : 43x / 20 = 1032

=> x = 1032 * 20 / 43 = 480

Hence the cost price of each toy = Rs 480

Alternatively,

(105% + 110 %) of the Cost price of the toy = Rs1032

=> 215% of the Cost price of the toy = Rs1032

=> Cost price of the toy = Rs 1032 * 100 / 215 = Rs 480

2) (25% – 20%) of the Cost price of the bicycle = Rs 89

=> 5% of the Cost price of the bicycle = Rs 89

=> Cost price of the bicycle = Rs 89 * 100 / 5 = Rs 89 * 20 = Rs 1780

TRY THE REST OR ASK ONE AT A TIME

1) 1.05x + 1.10x = 1,032

2.15x = 1,032

x = 480

2) 1.2x + 89 = 1.25x

89 = 0.05x

x = 1,780

3) Not sure what you mean.

4) 1.2(0.85x – 0.085x) = 91.8%

5) 1.2x – 0.12x = 1.08x

0.08x = 544

x = 6,800

6) Not sure what you mean.

7) Not sure what you mean.