i need help finding the original price. the problem is a camera is on sale at 28% off the usual price. The amount of the discount is $100.80. what was the original price of the camera?

## Need Help With This Math Problem?

May 31st, 2013 admin

May 31st, 2013 admin

i need help finding the original price. the problem is a camera is on sale at 28% off the usual price. The amount of the discount is $100.80. what was the original price of the camera?

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The simple way is saying that 100.80 is 72% of what? Or 100.8 = .72x. You just divide both sides by .72 to get 100.8/.72 = x

Nice way to justify your nick, Ignoramous. The question said 28% off the price, not of the price.

100% – 28% = 72%

72%/100 = 0.72

100.80 = 0.72x

x = 100.80/0.72 = $140.00 original price of camera

– .–

If the question means exactly what it says that the AMOUNT of the discount is $100.80, then the $100.80 represents 0.28 of the usual price.

Therefore the original price = 100.80 / 0.28 = $360

The original price of the camera is: $360

28% of $360 = $100.80

Since the problem says 28% off, you will subtract it from 100 and get:

100-28 = 72

The 72% divided by 100 will giver you:

72/100 = .72

This is basically .72 (72%) of something, which can be called x. You will multiply the .72 and x and get:

.72x = 100.80

To solve for x, you will divide both sides by .72 and get:

.72x/.72 = 100.80/.72

The .72/.72 will cancel out, and you will be left with:

x = 100.80/.72

And….the original price is:

x = 140

Hope this helps